I designed with the choice simulator 3 products based on HB-model and got the following shares of preferences and the std errors:

Shares of preferences:

1: 27.4%

2: 23.3%

3: 22.9%

None-Option: 26.5%

Std. Error:

1: 1,32627%

2: 1,08949%

3: 1,10678%

None: 1,22438%

I would to make sure, that the share of preferences are significant.

Can I test it like this? (similar to 12D in Becoming an Expert in Conjoint Analysis)

→ t (1/2) = 27.1-23.3 / square root(0.0132627²+0.0108949²) = 240.76

→ t (1/3) = 27.1-22.9/ square root(0.0132627²+0.0110678²) = 264.25

→ t (1/4) = 27.1-26.5/ square root(0.0132627²+0.0122438²) = 50.87

→ t (2/3) = 23.3-22.9/ square root(0.0108949²+0.0110678²) = 4.43598

→ t (2/4) = 23.3-26.5/ square root(0.0108949²+0.0122438²) = -35.428

→ t (3/4) = 22.9-26.5/ square root(0.0110678²+0.0122438²) = -218.119

Since all t-values has an absolute magnitude greater than 2.58, it is greater than 99% confident.

Is that right or do I have to test in different?

Thank you an best regards,

Beatrice